Calculating engine displacement

[Dr.Evil]

I am just courious as to what size (displacement) the following engine would be:
3.0 Bored .030 over
crank turned .10 under and indexed
I know the boring .030 over added a few cubes, but what about about the ofset ground crank/indexing?

Does anyone have the stock bore and stroke for the 3.0?
Thanks

 

[AutoSHO]

The formula for finding displacement in cubic inches is:

(Pi/4) * (Bore)^2 * Stroke * # of Cyls

For a .030" over 3.0,

3.141592654/4 * (3.53)^2 * 3.15 * 6 = 184.97 cubic inches.

Divide that number by 61.024 to get the displacement in liters: 3.03L.

I'm not sure if I understood your post correctly, but it sounds like you're just having the rod journals machined undersize, which does not change stroke. If you are having them offset ground .01", then...

3.141592654/4 * (3.53)^2 * 3.16 * 6 = 185.56 Cubic Inches = 3.04L

 

[Hack]

For future use, this site has a bunch of automotive related formulas. You just plug in the numbers and go. Just make sure your pop-up blocker is enabled.
http://murray.faithweb.com/formulas.htm#disp_standard